For objects in uniformly accelerated rectilinear motion, the five quantities, displacement x, the time took t, initial velocity v_{0}, final velocity v and acceleration a are related by a set of simple equations called **kinematic equations of motion** :

if the position of the object at time t = 0 is 0. If the particle starts at x = x_{0} , x in above equations is replaced by (x- x_{0}).

## Kinematical Graphs

The ‘displacement-time’ and the ‘velocity-time’ graphs of a particle are often used to provide us with a visual representation of the motion of a particle. The ‘shape’ of the graphs depends on the initial ‘co-ordinates’ and the ‘nature’ of the acceleration of the particle (Fig.)

## Equations of Uniformly Accelerated Motion

If a body starts with velocity (u) and after time t its velocity changes to v, if the uniform acceleration is a and the distance traveled in time t in s, then the following relations are obtained, which are called equations of uniformly accelerated motion.

- v = u + at
- s = ut + at
^{2} - v
^{2}= u^{2}+ 2as

Distance traveled in nth second

If a body moves with uniform acceleration and velocity changes from u to v in a time interval, then the velocity at the midpoint of its path

**√u ^{2} + v^{2}/ 2**

## Motion under Gravity

If an object is falling freely (u = 0) under gravity, then equations of motion

*v = u + gt**h =ut +gt*^{2}*v*^{2}= u^{2}+ 2gh

**Note:** If an object is thrown upward then g is replaced by – g in above three equations. It thus follows that

### Time is taken to reach maximum height:

### Maximum height reached by the body:

A ball is dropped from a building of height h and it reaches after t seconds on earth. From the same building if two balls are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after t, and t_{2} seconds respectively, then

When a body is dropped freely from the top of the tower and another body is projected horizontally from the same point, both will reach the ground at the same time.

## How useful was this post?

Click on a star to rate it!

Average rating 5 / 5. Vote count: 1

## We are sorry that this post was not useful for you!

Let us improve this post!

Thanks for your feedback!